Duck
Joined: Sep 01, 2003
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  Posted:
Jan 07, 2004 - 19:13 |
 
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If you dodge into 3 TZ, with an AG6 player, a roll of 3 is enough to succeed…how come? LRB state that you get a modifier of +1 for the dodge and -1 per TZ. So the roll of 3 will be: 3+1-3=1 => fail! The same thing applies with catch. Is it a bug, or have I missed something?!?!
/Duck |
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Mezir
Joined: Aug 02, 2003
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| Posted:
Jan 07, 2004 - 19:18 |
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The rules only ever state that a modified 1 fails in the case of passing. Otherwise you only need to hit the target stated on the agility table.
For AG 6 your Target Number is 1. The end result was a 1. The action is successful, since it was not a pass.
A natural one will still fail though.  |
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Duck
Joined: Sep 01, 2003
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| Posted:
Jan 07, 2004 - 19:31 |
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Oh, I see. It is because of the fumble rule, with passing, there is a difference. Thankyou!!!
/Duck |
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dinaturz
Joined: Aug 02, 2003
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| Posted:
Jan 07, 2004 - 19:35 |
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the number are correct.
what is wrong is "1 => fail!".
LRB 2.0, page 9
| Quote: | A roll of 1 before modification always fails and a roll of 6 before
modification always succeeds. |
Note: the bold is mine.
Since a 1 as final result is not a failure, 3 is the minimum required to pass the dodge roll.
marco |
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