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DeathAdder
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2009

2009-05-21 14:29:23
rating 1.6
2009-05-21 14:29:23
28 votes, rating 1.6
Dice odds


each dice has 6 sides

1POW
1DEFENDER STUMBLES
2PUSH BACK
1BOTH DOWN
1ATTACKER DOWN


hence a 1d block

the arrows give a 32.5% chance
the explosion has a 16.25% chance
the explosion w/! has a 16.5% chance
the skull has a 16.5% chance
the skull w/explosion has a 16.5% chance
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Comments
Posted by Shades_SteelFist on 2009-05-21 14:33:34
learn the right terms mate, its

POW
POW!
Push
Both Down
Atk down
Posted by Astarael on 2009-05-21 15:54:52
Actually there's multiple terms depending on what you look at.

My recollection is:

POW
POW!
PUSH
SKULL/POW
SKULL

Either way i want to know why the explosion is .25% less likely than the other 1 sides :P
Posted by DonTomaso on 2009-05-21 16:10:50
Astarael: Because the ! is heavy, and thus not so likely to end up on top...
=o)

Never played craps?
Posted by James_Probert on 2009-05-21 23:21:27
Hmmmmm

your percentages don't add up

32.5+16.25+16.5+16.5+16.5 = 98.25

where has the 1.75% gone?

Clearly on a perfect random number generator, assuming that it will generate an integer between 1 and 6,
translating 1 = skull
2 = skull/pow
3 = push
4 = push
5 = pow!
6 = pow

then the percentages should be:
push = 33.3%
Skull = 16.7%
Skull/pow = 16.7%
pow! = 16.7%
pow = 16.7%


P.S. my percentages don't add up due to rounding
Posted by Irgy on 2009-05-22 00:17:30
Apparently, I've heard the scatter dice has 8 equivalent sides, giving:

12.5% North
12.5% NE
12.5% East
12.5% SE
12.5% South
12.5% SW
12.5% West, and
12.5% NW

Keep this in mind when thinking about where the ball might bounce!